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Match the following:

compound oxidation state
(I) \mathrm{H}_2 \mathrm{~S} A) +6
(II) \mathrm{H}_2 \mathrm{~S}_{2}\mathrm{~O}_{3} B) +1
(III) \mathrm{S}_2 \mathrm{Cl}_{2} C) -2
(IV) \mathrm{Na}_2 \mathrm{SO}_{3} D) +4

 

Option: 1

I-A, II-B, III-C, IV-D

 


Option: 2

I-B, II-A, III-D, IV-C

 


Option: 3

I-D, II-C, III-B, IV-A

 


Option: 4

I-C, II-A, III-B, IV-D


Answers (1)

best_answer

H_{2}S has sulphur in -2 state because it is a hydride, H_{2}S_{2}O_{3} has sulphur in +6 state, S_{2}Cl_{2} has sulphur in +1 because chlorine is in -1 oxidation state. Finally, sulphur in Na_{2}SO_{3} has +4 oxidation state.

 

Posted by

shivangi.shekhar

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