Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Match the following:

Compound Oxidation State

I) $\mathrm{HRuO_4}$ A) $+3$

II) $\mathrm{HNO_2}$ B) $+7$

III) $\mathrm{HPO_3}$ C) $+6$

IV) $\mathrm{H_6O_sO_6}$ D) $+5$

Option: 1
I-A, I-C, III-D, IV-B

Option: 2
I-B, II-A, III-D, IV-C

Option: 3
I-D, II-C, III-B, IV-A

Option: 4
I-C, II-B, III-A, IV-D

Answers (1)

$\mathrm{Ru}$ has $+7$ oxidation state in $\mathrm{HRuO_4}$ , $\mathrm{N}$ has $+3$ oxidation state in $\mathrm{HNO_2}$ , $\mathrm{P}$ has $+5$ oxidation state in $\mathrm{HPO_3}$ and $\mathrm{O_s}$ has $+6$ oxidation state in $\mathrm{H_6O_sO_6}$ .

Hence option 2 is correct.

Posted by

Ramraj Saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Trending Articles/News

anam-khan

JEE Main 2026: NTA reopens Session 2 registration; apply by March 13 at jeemain.nta.nic.in

anam-khan

JEE Mains 2026 LIVE: NTA session 2 city slip soon; admit card, exam dates, here's how to prepare

anam-khan

JEE Main 2026 session 2 application correction begins on jeemain.nta.nic.in; edit details by tomorrow

Latest Question