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Match the following:

Compound(atom) Oxidation State of Atom
(I) \mathrm{NO}\mathrm{(N)} (A) +1
(II) \mathrm{H}_{2}\mathrm{O}_{2}\mathrm{(O)} (B) -1
(III) \mathrm{MnO}_{4}^{-}\mathrm{(Mn)} (C) +2
(IV) \mathrm{N}_{2}\mathrm{H_{2}}\mathrm{(N)} (D) +7

 

Option: 1

I-A, II-B, III-C, IV-D

 


Option: 2

I-C, II- B, III- D, IV- A

 


Option: 3

I-D, II-B, III-A, IV-C

 


Option: 4

I-C, II-A, III-D, IV-B


Answers (1)

best_answer

For NO, O has -2 charge so N has +2 charge.

For \mathrm H_{2}\mathrm {O}_{2}, H has +1 charge and there are two hydrogens so, +2 charge. For, both oxygen atoms the charge is -2 and each will have -1 charge.

For MnO_{4}^{-}, lets assume Mn has x charge. Then x+ (-2 X 4) = -1 =>   x-8 =-1 => x =+7

For N_{2}H_{2}, there are two hydrides. So, the charge is -2 for hydrogens. For two nitrogen atoms the charge becomes +2 to make the molecule neutral. So each nitrogen atom has +1 charge.

 

 

Posted by

Pankaj Sanodiya

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