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\mathrm{m} men and \mathrm{w} women are to be seated in a row so that all women sit together. The number of ways in which they can be seated is

Option: 1

\mathrm{(m+1) ! w !}


Option: 2

\mathrm{m ! w !}


Option: 3

\mathrm{m !(w-1)!}


Option: 4

\mathrm{{ }^{m+w} C_{w}}


Answers (1)

best_answer

 Treating \mathrm{w} women as one block, we can permute \mathrm{m} men and one block in \mathrm{(m+1) ! } ways and women in the block in \mathrm{w ! } ways. Thus, the required number of ways is \mathrm{(m+1) ! w ! }

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