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n identical cells are joined in series with two cells A and B with reversed polarities. Emf of each cell is E and internal resistance is r. Potential difference across cell A or B is: (n > 4)

Option: 1

\frac{2 E}{n}


Option: 2

2 E\left(1-\frac{1}{n}\right)


Option: 3

\frac{4 E}{n}


Option: 4

2 E\left(1-\frac{2}{n}\right)


Answers (1)

best_answer

Current in the circuit will be : I=\frac{(n-4) E}{n r}
Hence, potential difference across A and B is
\mathrm{V}=\mathrm{E}+\mathrm{Ir}=\mathrm{E}+\frac{(n-4) E}{n r} \cdot V=2 \mathrm{E}\left(1-\frac{2}{n}\right)

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Divya Prakash Singh

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