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\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-} should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is (-) __________ \mathrm{ \Delta_{0}}. (Nearest integer)

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\left [ Fe(CN)_{6} \right ]^{3-}} is an inner orbital complex,


Due to strong field ligand \mathrm{CN^{\Theta }} the electron will be paired .

So, \mathrm{CFSE= 5\times \left ( -0.4 \right )\Delta _{0}+pairing\, energy}

Now, for complex ingoring the pairing energy

Hence \mathrm{CFSE= 5\times \left ( -0.4\, \Delta _{0} \right )}
            \mathrm{CFSE= -2\Delta _{0}}

Ans = 2
 

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mansi

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