Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Need clarity, kindly explain! A simple pendulum of length L is placed between theplates of a parallal plate capacitor having electric field E, as shown in figure. its bob has mass m and charge q. The time period of the pendulum is given by:

A simple pendulum  of length L is placed between theplates of a parallal plate capacitor having electric field E, as shown in figure. its bob has mass m and charge q. The time period of the pendulum is given by:

  • Option 1)

    2\pi \sqrt{\frac{L}{\sqrt{g-\frac{qE}{m}}}}

     

  • Option 2)

    2\pi \sqrt{\frac{L}{\sqrt{g^{2}-\frac{q^{2}E^{2}}{m^{2}}}}}

     

  • Option 3)

    2\pi \sqrt{\frac{L}{g+\frac{qE}{m}}}

  • Option 4)

    2\pi \sqrt{\frac{L}{\sqrt{g^{2}+\left ( \frac{qE}{m} \right )^{2}}}}

Answers (1)

best_answer

Two force act on the mass m

1) gravity force

2) force by electric field.

net force on m is =\sqrt{\left ( mg \right )^{2}+\left ( qE \right )^{2}}

So, net g is =\sqrt{ g ^{2}+\left ( qE \right/m )^{2}}

T=2\pi \sqrt{\frac{l}{g}}

=2\pi \sqrt{\frac{l}{\sqrt{g^{2}+\left ( \frac{qt}{m} \right )^{2}}}}


Option 1)

2\pi \sqrt{\frac{L}{\sqrt{g-\frac{qE}{m}}}}

 

Option 2)

2\pi \sqrt{\frac{L}{\sqrt{g^{2}-\frac{q^{2}E^{2}}{m^{2}}}}}

 

Option 3)

2\pi \sqrt{\frac{L}{g+\frac{qE}{m}}}

Option 4)

2\pi \sqrt{\frac{L}{\sqrt{g^{2}+\left ( \frac{qE}{m} \right )^{2}}}}
Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in
anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation

Latest Question