Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

A 5 V battery with internal resistance $2\Omega$ and 2 V battery with internal resistance $1\Omega$ are connected to a $10\Omega$ resistor as shown in the figure. The current in the $10\Omega$ resistor is

Option 1)
$0.27 A\: \: P_{1}\: \: to\: \: P_{2}$

Option 2)
$0.27 A\: \: P_{2}\: \: to\: \: P_{1}$

Option 3)
$0.03 A\: \: P_{1}\: \: to\: \: P_{2}$

Option 4)
$0.03 A\: \: P_{2}\: \: to\: \: P_{1}$

Answers (1)

best_answer

As we learnt in

In closed loop -

$-i_{1}}R_{1} + i_{2}}R_{2} -E_{1}-i_{3}}R_{3}+E_{2}+E_{3}-i_{4}}R_{4}=0$

- wherein

Applying Kirchhoff’s law for the loops

$AP_{2}P_{1}CA\: \: and \: \: P_{2}BDP_{1}P_{2}\: \: one \: \: gets$

$-10y-2x+5=0$

$\Rightarrow 2x+10y=5\cdots \cdots \cdots \cdots (i)$

$+2-1(x-y)+10.y=0$

$+x-11y=2\cdots \cdots \cdots \cdots (ii)$

$2x-22y= 4\cdots \cdots \cdots \cdots (iii)=(ii)\times 2$

$(i)-(iii)gives\ 32 y=1$

$\Rightarrow y=\frac{1}{32}A= 0.03A from P_{2}\: \: to\: \: P_{1}$

Option 1)

$0.27 A\: \: P_{1}\: \: to\: \: P_{2}$

This option is incorrect.

Option 2)

$0.27 A\: \: P_{2}\: \: to\: \: P_{1}$

This option is incorrect.

Option 3)

$0.03 A\: \: P_{1}\: \: to\: \: P_{2}$

This option is incorrect.

Option 4)

$0.03 A\: \: P_{2}\: \: to\: \: P_{1}$

This option is correct.

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: Hardwired to excel? Know BTech electrical engineering cut-offs at NITs

anam-khan

JEE Main 2025 chemistry needs conceptual understanding; 5 tips to score high

anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon; paper pattern, exams from January 22

Latest Question