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  • Need clarity, kindly explain! - Electrostatics - JEE Main-13

A parallel plate capacitor has 1\mu F capacitance. One of its two plates is given +2\mu C chargre and the other plate, +4\mu C charge. The potential difference developed across the cpacitor is:

  • Option 1)

    3 V

  • Option 2)

    1V

  • Option 3)

    5V

  • Option 4)

    2V

Answers (1)

best_answer

V=\frac{Q}{C}=\frac{1\mu C}{1 \mu f}=1\; volt


Option 1)

3 V

Option 2)

1V

Option 3)

5V

Option 4)

2V

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