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  • Need clarity, kindly explain! iIf three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is :

iIf three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is : 

  • Option 1)

    \frac{1}{5}

  • Option 2)

    \frac{3}{20}

  • Option 3)

    \frac{3}{10}

  • Option 4)

    \frac{1}{10}

 

Answers (1)

Only two equilateral triangle are possible A_{1}A_{3}A_{5} and A_{21}A_{4}A_{6}

 

\frac{2}{6C_{_{_{5}}}}=\frac{2}{20}=\frac{1}{10}


Option 1)

\frac{1}{5}

Option 2)

\frac{3}{20}

Option 3)

\frac{3}{10}

Option 4)

\frac{1}{10}

Posted by

Vakul

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