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  • Need clarity, kindly explain! In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4 A, then that in the secondary coil is

In a transformer, number of turns in the primary coil are 140 and that in the secondary coil are 280. If current in primary coil is 4 A, then that in the secondary coil is

  • Option 1)

    4 A

  • Option 2)

    2 A

  • Option 3)

    6 A

  • Option 4)

    10 A

 

Answers (1)

best_answer

As we learnt in 

For Ideal transformer -

\frac{\varepsilon _{s}}{\varepsilon _{P}}= \frac{N _{s}}{N _{P}}= \frac{V_{s}}{V _{P}}= \frac{{i}' _{P}}{{i}'_{s}}
 

- wherein

\varepsilon _{s}\rightarrow induced e.m.s.in secondary

\varepsilon _{P}\rightarrow induced e.m.s.in primary

 

 \frac{V_{2}}{V_{1}}=\frac{N_{2}}{N_{1}}=\frac{I_{1}}{I}_{2}

\therefore \frac{I_{2}}{I}_{1}=\frac{N_{1}}{N_{2}}=\frac{140}{280}=\frac{1}{2}

\therefore I_{2}=\frac{I_{1}}{2}=\frac{4}{2}=2A


Option 1)

4 A

This option is incorrect

Option 2)

2 A

This option is correct

Option 3)

6 A

This option is incorrect

Option 4)

10 A

This option is incorrect

Posted by

Aadil

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