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  • Need clarity, kindly explain! - Oscillations and Waves - JEE Main-2

A body is executing simple harmonic motion with a angular frequency 2\; rad/s. The velocity of the body  at 20 mm displacement when the amplitude of the motion is 60 mm is

  • Option 1)

    40\; mm/s

  • Option 2)

    60\; mm/s

  • Option 3)

    113\; mm/s

  • Option 4)

    120\; mm/s

 

Answers (1)

best_answer

v = \omega\sqrt{a^{2} - y^{2}} = 2\sqrt{60^{2} - 20^{2}} = 113 mm/s

 

Equation of S.H.M. -

a=-\frac{d^{2}x}{dt^{2}}= -w^{2}x

w= \sqrt{\frac{k}{m}}

 

- wherein

x= A\sin \left ( wt+\delta \right )

 

 

 


Option 1)

40\; mm/s

This is incorrect.

Option 2)

60\; mm/s

This is incorrect.

Option 3)

113\; mm/s

This is correct.

Option 4)

120\; mm/s

This is incorrect.

Posted by

Avinash

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