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  • Need explanation for: A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is:

A block of mass M  is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force  exerted by the rope on the block is:

  • Option 1)

    \frac{Pm}{M+m}

  • Option 2)

    \frac{Pm}{M-m}

  • Option 3)

    P

  • Option 4)

    \frac{PM}{M+m}

 

Answers (1)

best_answer

As we learnt in

Motion when block are connected with string -

T=m_{1}a

F-T=m_{2}a

- wherein

a=\frac{F}{m_{1}+m_{2}}


T=\frac{m_{1}F}{m_{1}+m_{2}}

 

 

 

:        Acceleration of block  (a)= \frac{Force \: \: applied }{Total \: mass}

or          a=\frac{P}{(M+m)}

        Force on block   = Mass \: of \: block\times a=\frac{MP}{(M+m)}.

Correct option is 1.


Option 1)

\frac{Pm}{M+m}

This is the correct option.

Option 2)

\frac{Pm}{M-m}

This is an incorrect option.

Option 3)

P

This is an incorrect option.

Option 4)

\frac{PM}{M+m}

This is an incorrect option.

Posted by

divya.saini

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