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  • Need explanation for: An object is located in a fixed position in front of a screen. Sharp image is obtained on the screen for two positions of a thin lens separated by 10 cm. The size of the images in two situations are in the ratio 3 : 2. What is t

 An object is located in a fixed position in front of a screen. Sharp image is obtained on the screen for two positions of a thin lens separated by 10 cm. The size of the images in two situations are in the ratio 3 : 2. What is the distance between the screen and the object ?

  • Option 1)

     124.5 cm

  • Option 2)

       144.5 cm

  • Option 3)

      65.0 cm

  • Option 4)

       99.0 cm

 

Answers (1)

best_answer

As we have learned

Magnification at two position of lens -

m_{1}= \frac{D\, +d}{D-d}

m_{2}= \frac{D\, -d}{D+d}
 

- wherein

m_{1}=Mangnification at position 1 of lens.

m_{2}=Mangnification at position 2

 

 

\frac{m_{1}}{m_{2}}=\frac{3}{2}=\left ( \frac{D\, +10 }{D-10} \right )^2 \\ D = 99 cm


Option 1)

 124.5 cm

Option 2)

   144.5 cm

Option 3)

  65.0 cm

Option 4)

   99.0 cm

Posted by

Avinash

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