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Let the orthocentre and centroid of a triangle be A(−3, 5) and B(3, 3) respectively. If C is the circumcentre of this triangle, then the radius of the circle having line segment AC as diameter, is :

  • Option 1)

    \frac{3\sqrt5}{2}

  • Option 2)

    \sqrt10

  • Option 3)

    2\sqrt10

  • Option 4)

    3\sqrt\frac{5}{2}

 

Answers (2)

best_answer

This is the Euler's line  \frac{2x-3}{3}=3 \Rightarrow x=6

\frac{2y+5}{3}=3 \Rightarrow y=2

point :(6,2)

Distance AB = \sqrt({9^{2}}+ 3^{2}) = \sqrt{90}= 3\sqrt10

radius \frac{3\sqrt10}{2}= 3\sqrt{\frac{5}{2}}

 

Euler line -

In any non equilateral triangle the circumcentre (O), the centriod (G) and the orthocentre (H) are collinear and G divides OH in ratio 1:2

- wherein

 

 


Option 1)

\frac{3\sqrt5}{2}

Option 2)

\sqrt10

Option 3)

2\sqrt10

Option 4)

3\sqrt\frac{5}{2}

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Plabita

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