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  • Nitrogen gas at temp. The temp(in K) at which the rms speed of &nb

Nitrogen gas at 300^{\circ}temp. The temp(in K) at which the rms speed of H_{2}  molecule would be equal to the rms speed of a nitrogen molecule is (Molar mass of N_{2} gas is 28gm).
Upto 2 digit after decimal
Option: 1 40.94
Option: 2 81
Option: 3 32
Option: 4 273

Answers (1)

best_answer

Correct Answer: 41

V_{rms}=\sqrt{\frac{3RT}{M}}

For N2 T_1=300+273.15=573.15 K \ and \ \ M_1=28

For H2 \frac{V_{N_2}}{V_{H_2}}=1=\sqrt{\frac{T_1}{T_2}*\frac{M_2}{M_1}}=\sqrt{\frac{573.15}{T}*\frac{2}{28}}\\T=40.94 K

Posted by

Deependra Verma

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