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  • of a certain monoatomic ideal gas undergoes a temperature increase of <img alt="\mathrm{40 \! \!

\mathrm{7 \mathrm{~mol}} of a certain monoatomic ideal gas undergoes a temperature increase of \mathrm{40 \! \! \mathrm{~K}} at constant pressure. The increase in the internal energy of the gas in this process is :

\mathrm{\text { (Given } \mathrm{R}=8.3 \; \mathrm{JK}^{-1} \mathrm{~mol}^{-1} \text { ) }}

Option: 1

\mathrm{5810 \mathrm{~J}}


Option: 2

\mathrm{3486 \mathrm{~J}}


Option: 3

\mathrm{11620 \mathrm{~J}}


Option: 4

\mathrm{6972 \mathrm{~J}}


Answers (1)

\mathrm{n =7 \quad V=5 / 3 }

\mathrm{p =\text { constant } }

\mathrm{\Delta T =40 \mathrm{~K} }

\mathrm{\Delta U=\frac{n R \Delta T}{V-1} }

\mathrm{=\frac{7(8.3) \times 40}{2 / 3} }

\mathrm{=420 \times 8.3 }

\mathrm{\Delta U =3486 \mathrm{~J}}

Hence (2) is correct option.





 

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Kshitij

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