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  • One end of a horizontal thick copper wire of length 2L and radius 2R is welded to an end of another horizontal thin copper wire of length L and radius R. When the arrangement is stretched by applyi

One end of a horizontal thick copper wire of length 2L and radius 2R is welded to an end of another horizontal thin copper wire of length L and radius R. When the arrangement is stretched by applying forces at two ends, the ratio of elongation in the thin wire to that in the thick wire will be 

Option: 1

4


Option: 2

2


Option: 3

1


Option: 4

5


Answers (1)

best_answer

The elongation in the thin wire 

\therefore \quad \Delta l=\frac{F L}{A Y}=\frac{F L}{\left(\pi r^2\right) Y} \Rightarrow\bigtriangleup l\alpha \frac{L}{A}

\therefore \quad \frac{\Delta l_1}{\Delta l_2}=\frac{L / R^2}{2 L /(2 R)^2} \Rightarrow 2

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Irshad Anwar

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