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\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 paper acidified with dilute \mathrm{H}_2 \mathrm{SO}_4 turns green when exposed to

Option: 1

Carbon dioxide


Option: 2

Sulphur trioxide


Option: 3

Sulphur dioxide


Option: 4

Hydrogen sulphide


Answers (1)

best_answer

\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7+2 \mathrm{H}^{+}+\mathrm{SO}_2 \rightarrow \underset{\text { (green) }}{2 \mathrm{Cr}^{+3}}+3 \mathrm{SO}_4^{-2}+\mathrm{H}_2 \mathrm{O}

Posted by

Sanket Gandhi

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