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  • Photons of energy  are incident on cathode.Electrons reaching the anode have kin

Photons of energy 5 \mathrm{~eV} are incident on cathode.Electrons reaching the anode have kinetic energies varying from 6 \mathrm{~eV} to 8 \mathrm{~eV}. 

Then which of the following is true?

Option: 1

Work function of the metal is 2 \mathrm{eV}

 


Option: 2

 Work function of the metal is 3 \mathrm{eV}


Option: 3

 Current in the circuit is equal to saturation value
 


Option: 4

Both (1) and (3)


Answers (1)

best_answer

Maximum kinetic enegy,  \mathrm{K}_{\max }=(5-\phi) \mathrm{eV}

When these electrons are accelerated through 5 \mathrm{~V},

they will reach the anode with maximum energy = (5-\phi+5) \mathrm{eV}

\therefore 10-\phi=8 \quad \ or \ \phi=2 \mathrm{eV} 

Current is less than saturation current because even if the slowest electron reaches the plate it will have 5 \mathrm{eV} energy at the anode, but there it is given that the minimum energy is  6 \mathrm{eV}.

Posted by

Irshad Anwar

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