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The common tangent to the circle x^{2}+y^{2}=4\:\:and\:\:x^{2}+y^{2}+6x+8y-24=0  also passes through the point :

  • Option 1)

    (4,-2)

  • Option 2)

    (-6,4)

  • Option 3)

    (6,-2)

  • Option 4)

    (-4,6)

 

Answers (1)

best_answer

x^{2}+y^{2}-4=0

\\x^{2}+y^{2}+6x+8y-24=0

common tangent will  be  s_{1}-s_{2}=0

\\6x+8y=20\\\\\:3x+4y=10\\\\\:hence \:\:point \:(6,-2)\:\:lies\:\:on\:\:above \:\:line.


Option 1)

(4,-2)

Option 2)

(-6,4)

Option 3)

(6,-2)

Option 4)

(-4,6)

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