A screw gauge gives the following reading when used to measure the diameter of a wire.
Main scale reading : 0 mm
Circular scale reading : 52 divisions
Given that 1 mm on main scale corresponds to 100 divisions of the circular scale.
The diameter of wire from the above data is :
0.52 cm
0.052 cm
0.026 cm
0.005 cm
As we learnt in
To measure the diameter of small spherical cylindrical body using Vernier Callipers -
Vernier Constant
= 1 Main scale division - 1 V.S. Division
V.C= 1 M.S.D - 1 V.S.D
M.S.D= Main Scale Reading
V.S.D= Vernier Scale Reading
- wherein
Total observed reading =
N= Nth division
Observations:
1. Vernier constant (least count) of the Vernier Callipers:
1 M.S.D. = 1 mm
10 vernier scale divisions = 9 main scale divisions
i.e. 10 V.S.D. = 9 M.S.D.
1 V.S.D. = M.S.D.
Vernier Constant (L.C.) = 1 M.S.D. - 1 V.S.D. = 1 M.S.D. M.S.D.
2. Zero error: (i) ........ cm (ii) ............cm (iii) ..........cm
Mean Zero Error (e) = ............ cm
Mean Zero Correction (c) = - (Mean Zero Error)
= .......... cm
Least count of screw gauge=
Option 1)
0.52 cm
This option is incorrect
Option 2)
0.052 cm
This option is correct
Option 3)
0.026 cm
This option is incorrect
Option 4)
0.005 cm
This option is incorrect
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