Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Please,please help me - Current Electricity - JEE Main-3

For the circuit shown, with R_{1}=1.0\; \Omega, R_{2}=2.0\; \Omega, E_{1}=2\; V and E_{2}=E_{3}=4\; V, the potential difference between the points 'a' and 'b' is approximately(in V) :

  • Option 1)

    2.7

  • Option 2)

    3.7

  • Option 3)

    3.3

     

  • Option 4)

    2.3

Answers (1)

best_answer

R_{1}=1\: \Omega , E_{1}=2\; v

E_{2}=4\; v, E_{3}=4\; v, R_{2}=2\; \Omega

For parallal combination of cells

\varepsilon _{a}=\frac{\frac{\varepsilon _{1}}{r_{1}}+\frac{\varepsilon _{2}}{r_{2}}+\frac{\varepsilon _{3}}{r_{3}}....}{\frac{1}{r_{1}}+\frac{1}{r_{2}}+\frac{1}{r_{3}}.....}=\frac{\frac{2}{2}+\frac{4}{2}+\frac{4}{2}}{\frac{1}{2}+\frac{1}{2}+\frac{1}{2}}

\varepsilon _{a}=\frac{10}{3}=3.3\; V


Option 1)

2.7

Option 2)

3.7

Option 3)

3.3

 

Option 4)

2.3

Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 Registration LIVE: NTA application open soon on jeemain.nta.nic.in; exam from January 21
anam-khan

JEE Main 2026: Minimum marks to secure top 1000 rank in JEE Advanced; rank vs score trend over 5 years
anam-khan

JEE Main 2026 Aadhaar Authentication: How to fix name mismatch during registration?

Latest Question