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  • Please,please help me - Electromagnetic Induction and Alternating currents - JEE Main-3

The power factor of an  AC circuit having resistance (R)  and inductance (L)  connected in series and an angular velocity \omega is :

  • Option 1)

    R/\omega L

  • Option 2)

    R/(R^{2}+\omega^{2} L^{2})^{1/2}

  • Option 3)

    \omega L/R

  • Option 4)

    R/(R^{2}-\omega^{2} L^{2})^{1/2}

 

Answers (1)

As we learnt in 

LR  Circuit Voltage -

V_{R}= IR

V_{L}= {I}X_{L}

- wherein

 

 

z=R+jX_{L}

=R+j(wl)\\ \left | z \right |=\sqrt{R^{2}+{ \omega^{2}}L^{2}}

Power factor=\frac{R}{\left | z \right |}

=\frac{R}{\sqrt{R^{2}+\omega^{2}L^{2}}}


Option 1)

R/\omega L

This option is incorrect

Option 2)

R/(R^{2}+\omega^{2} L^{2})^{1/2}

This option is correct

Option 3)

\omega L/R

This is incorrect

Option 4)

R/(R^{2}-\omega^{2} L^{2})^{1/2}

This is incorrect

Posted by

Vakul

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