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  • Please,please help me The ionization potential of a hydrogen atom is 13.6 volt. The energy required to remove an electron from the second orbit of hydrogen is:

The ionization potential of a hydrogen atom is 13.6 volt. The energy required to remove an electron from the second orbit of hydrogen is:

  • Option 1)

    3.4 eV

     

  • Option 2)

    6.8 eV

     

  • Option 3)

     13.6 eV

     

  • Option 4)

     27.2 eV

     

 

Answers (1)

best_answer

@15408 

Ionization energy -

E_{ion }= E_{\infty }-E_{n }

=13.6\frac{Z^{2}}{n^{2}}

 

- wherein

Energy required to move an electron from ground state to n= \infty

 

Energy required to remove electron from 2nd bohr orbit is 

\Delta E= E_{0}\cdot \left ( \frac{1}{2^{2}-\frac{1}{\infty }} \right )= \frac{E_{0}}{4}=\frac{13.6}{4}ev

\Delta E=3.4eV

 


Option 1)

3.4 eV

 

This solution is correct.

Option 2)

6.8 eV

 

This solution is incorrect.

Option 3)

 13.6 eV

 

This solution is incorrect.

Option 4)

 27.2 eV

 

This solution is incorrect.

Posted by

prateek

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