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If \sin\theta = x, find \tan\theta ?

  • Option 1)

    \frac{x}{\sqrt{x^2 - 1}}

  • Option 2)

    \frac{1}{\sqrt{x^2 - 1}}

  • Option 3)

    \frac{x}{\sqrt{1- x^2}}

  • Option 4)

    \frac{1}{\sqrt{1 -x^2 }}

 

Answers (1)

best_answer

As we have learnt,

 

Trigonometric Ratios of Functions -

cosec\ \Theta = \frac{Hyp}{Opp}

\sec \Theta = \frac{Hyp}{Base}

\cot \Theta = \frac{Base}{Opp}

- wherein

Trigonometric Ratios of Functions 2

 

 Since, \sin\theta = \frac{x}{1}

\tan\theta = \frac{x}{\sqrt{1- x^2}}

 


Option 1)

\frac{x}{\sqrt{x^2 - 1}}

Option 2)

\frac{1}{\sqrt{x^2 - 1}}

Option 3)

\frac{x}{\sqrt{1- x^2}}

Option 4)

\frac{1}{\sqrt{1 -x^2 }}

Posted by

Himanshu

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