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  • Point on the curve <img alt="y^2=4(x-10)" src="https://ent

Point on the curve y^2=4(x-10)  which is nearest to the line x+y=4  may be

 

Option: 1

 (11, 2)


Option: 2

 (10, 0)


Option: 3

 (11, –2)


Option: 4

 None of these


Answers (1)

best_answer

P\left(x_0, y_0\right): p t on curve nearest to line.

Normal at P is perpendicular to the line

Normal at P  has slope "-\frac{y_0}{2} "

\therefore y_0=2 \text { and } x_0=11 ; P(11,-2)

Posted by

Kuldeep Maurya

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