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  • Primary voltage is , resistance of the primary winding is <img alt="\mathrm{R_p}" src="https://ent

Primary voltage is \mathrm{V_p}, resistance of the primary winding is \mathrm{R_p}. Turns in primary and secondary are respectively \mathrm{N_p} and Ns then secondary current in terms of primary voltage and secondary voltage respectively will be

Option: 1

\mathrm{\frac{V_p N_p}{R_p N_s}, \frac{V_s N_p^2}{R_p N_s^2}}


Option: 2

\mathrm{\frac{\mathrm{V}_p \mathrm{~N}_p^2}{\mathrm{R}_{\mathrm{p}} \mathrm{N}_{\mathrm{s}}}, \frac{\mathrm{V}_{\mathrm{s}}^2 \mathrm{~N}_\rho^2}{\mathrm{R}_{\mathrm{p}} \mathrm{N}_{\mathrm{s}}^2}}


Option: 3

\mathrm{\frac{V_p N_p}{R_p^2 N_s}, \frac{V_s N^2}{R_p^2 N_s^2}}


Option: 4

\mathrm{\frac{\mathrm{V}_\rho \mathrm{N}_p^2}{\mathrm{R}_{\mathrm{p}} \mathrm{N}_{\mathrm{s}}^2}, \frac{\mathrm{V}_{\mathrm{s}}^2 \mathrm{~N}_\rho}{\mathrm{R}_{\mathrm{p}}^2 \mathrm{~N}_{\mathrm{s}}}}


Answers (1)

best_answer

\mathrm{\frac{i_s}{i_p}=\frac{N_p}{N_s}} Now, according to the information given in the problem,\mathrm{i_p} can be calculated by using the formula,\mathrm{V=i R \text { so } \mathrm{i}_{\mathrm{s}}=\frac{\mathrm{V}_{\mathrm{p}}}{\mathrm{R}_{\mathrm{p}}} \times \frac{\mathrm{N}_p}{\mathrm{~N}_{\mathrm{s}}}}    (This is the secondary current in terms of \mathrm{V_p})

Now to rearrange the result obtained above, in terms of secondary voltage, we must replace the term of \mathrm{V_p} in the above result by \mathrm{V_s}. We know that \mathrm{\frac{V_p}{V_s}=\frac{N_p}{N_s} ; \quad V_p=\frac{V_s N_p}{N_s}} , Substituting this in equation (i) \mathrm{\mathrm{i}_{\mathrm{s}}=\frac{\mathrm{V}_{\mathrm{s}}}{\mathrm{R}_{\mathrm{p}}} \frac{\mathrm{N}_{\mathrm{p}}^2}{\mathrm{~N}_{\mathrm{s}}^2}}

Posted by

Kuldeep Maurya

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