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Rate constant for a reaction \mathrm{H}_2+\mathrm{I}_2 \rightleftharpoons 2 \mathrm{HI}  is 0.2 , then the rate constant for reaction  2 \mathrm{HI} \rightleftharpoons \mathrm{H}_2+\mathrm{I}_2  is -

Option: 1

0.2


Option: 2

2


Option: 3

5


Option: 4

1


Answers (1)

best_answer

Rate constant for backward (reverse) reaction is 

\mathrm{\mathrm{K}_{\mathrm{b}}=\frac{1}{K_f}=\frac{1}{0.2}=5}.

Posted by

Gautam harsolia

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