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\operatorname{Ln}^{3+}  show a coordination number of 6-12 and a wide variety of coordination environments when compared to transition metals. The correct reason is:

  1. More unpaired electrons in f-orbitals.
  2. Large size of the cations.
  3. Small size of the cations.
  4. Poor shielding effect of f-orbitals.
Option: 1

a and c     


Option: 2

b and c     


Option: 3

c and d   


Option: 4

a and b


Answers (1)

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The volume occupied by a \mathrm{Ln}^{3+} ion is typically four to five times that occupied by a typical 3d-metal ion. Also, the number of unpaired electrons and empty orbitals is much higher. Unlike the 3 \mathrm{d} metals, which rarely exceed a coordination number of 6 (with 4 being common too), compounds of lanthanoids often have high coordination numbers, typically between 6 and 12, and a wide variety of coordination environments.

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