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  • Solve it, Displacement between maximum potential energy position and maximum kinetic energy position for a particle executing SHM is

Displacement between maximum potential energy position and maximum kinetic energy position for a particle executing SHM is

  • Option 1)

    -a

  • Option 2)

    +a

  • Option 3)

    \pm a

  • Option 4)

    \pm \frac{a}{}4

 

Answers (1)

best_answer

Maximum potential energy position is  y = \pm a

and maximum kinetic energy position is   y = 0

 

Total energy in S.H.M. -

Total Energy = Kinetic + Potential Energy

- wherein

Total Energy =\frac{1}{2}K\left ( A^{2}-x^{2} \right )+\frac{1}{2}kx^{2}= \frac{1}{2}kA^{2}

Hence total energy in S.H.M. is constant

 

 

 


Option 1)

-a

This is incorrect.

Option 2)

+a

This is incorrect.

Option 3)

\pm a

This is correct.

Option 4)

\pm \frac{a}{}4

This is incorrect.

Posted by

divya.saini

View full answer

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