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The molality of 90% H_{2}SO_{4} solution is

[density=1.8 gm/ml]

  • Option 1)

    1.8

  • Option 2)

    48.4

  • Option 3)

    9.18

  • Option 4)

    94.6

 

Answers (1)

best_answer

As we learned

 

Relation between concentration terms (Molality & Molarity) -

\dpi{100} m=\frac{1000M}{1000d-Mm_{1}}

- wherein

m=Molality

M=Molarity

m_{1}=Molar\: mass\: of \: solute

\dpi{100} d=density\: of \: solution \: g/ml

 

 The density of solution = 1.8gm/ml
Weight of one litre of solution = 1800gm

 \therefore  Weight of H_{2}SO_{4} in the solution = =\frac{1800\times 90}{100}= 162gm

\therefore Weight of solvent =1800-1620 = 180gm

\therefore Molality = \frac{1620}{98}\times \frac{100}{180}=9.18

 


Option 1)

1.8

Option 2)

48.4

Option 3)

9.18

Option 4)

94.6

Posted by

Plabita

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