Get Answers to all your Questions

header-bg qa

Solve -5(x-1) \leq 10(2 x-3)
 

Option: 1

\left(-\infty, \frac{7}{5}\right)


Option: 2

\left(-\infty, \frac{7}{5}\right]


Option: 3

\left(\frac{7}{5}, \infty\right)


Option: 4

\left[\frac{7}{5}, \infty\right)


Answers (1)

best_answer

The correct option is (d)

\begin{aligned} -5(x-1) & \leqslant 010(2 x-3) \\ \Rightarrow \quad(x-1) & \geqslant \frac{10}{-5}(2 x-3) \end{aligned}

\begin{aligned} &\Rightarrow x-1 \geqslant-2(2 x-3) \\ &\Rightarrow x-1 \geqslant-4 x+6 \\ &\Rightarrow x+4 x \geqslant 6+1 \\ &\Rightarrow 5 x \geqslant 7 \\ &\Rightarrow x \geqslant \frac{7}{5} \end{aligned}

 

Posted by

Ajit Kumar Dubey

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE