Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Question is based on the following paragraph.

A nucleus of mass M\; +\; \Delta m\; is at rest and decays into two daughter nuclei of equal mass \frac{M}{2} each. Speed of light is c .

Question: The binding energy per nucleon for the parent nucleus is E_{1} and that for the daughter nuclei is E_{2} .Then

  • Option 1)

    E_{1}=2E_{2}\; \;

  • Option 2)

    \; E_{2}=2E_{1}\;

  • Option 3)

    \; \;E_{1}> E_{2}\;

  • Option 4)

    \; \; E_{2}>E_{1}

 

Answers (1)

best_answer

As we learnt in

Binding energy per nucleon -

 

- wherein

This graph shows the stability of nuclei many nuclear phenomena can be explained by this graph

 

 Product must be more stable than the original nucleus.

Hence, Binding energy of product > Binding energy of reactant.

\therefore\ \; E_{2}>E_{1}

Correct option is 4.


Option 1)

E_{1}=2E_{2}\; \;

This is an incorrect option.

Option 2)

\; E_{2}=2E_{1}\;

This is an incorrect option.

Option 3)

\; \;E_{1}> E_{2}\;

This is an incorrect option.

Option 4)

\; \; E_{2}>E_{1}

This is the correct option.

Posted by

perimeter

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Engineering aspirant dies by suicide in Kota, fourth case this year
anam-khan

What is non-Aadhaar declaration in JEE Main 2025? Explain mismatch between image, face
anam-khan

Forgot JEE Main password 2025 for downloading admit card? Here’s what to do

Latest Question