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Solution of x-3y-2z=0, 2x-y+4z=0, x-11y+14z=0 is

Option 1)
$\frac{x}{8}=\frac{y}{-10}=\frac{z}{7}=\lambda$

Option 2)
$\frac{x}{-10}=\frac{y}{8}=\frac{z}{7}=\lambda$

Option 3)
$\frac{x}{7}=\frac{y}{8}=\frac{z}{-10}=\lambda$

Option 4)
None of these

Answers (1)

best_answer

$x-3y-2z=0\\ 2x+y+4z=0\\ x-11y+14z=0$

1 -3 -2

2 +1 4 $\therefore \frac{x}{-12+2}=\frac{y}{-4-4}=\frac{z}{7}$

1 -11 14

$\frac{x}{-10}=\frac{y}{-8}=\frac{z}{7}=\lambda$

Option 1)

$\frac{x}{8}=\frac{y}{-10}=\frac{z}{7}=\lambda$

This solution is incorrect

Option 2)

$\frac{x}{-10}=\frac{y}{8}=\frac{z}{7}=\lambda$

This solution is correct

Option 3)

$\frac{x}{7}=\frac{y}{8}=\frac{z}{-10}=\lambda$

This solution is incorrect

Option 4)

None of these

This solution is incorrect

Posted by

divya.saini

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