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 Under what conditions will a pure sample of an ideal gas not only exhibit a pressure of 1 atm but also a concentration of  1 mol litre-1.   [ R = 0.082 litre atm mol-1 K-1 ]

  • Option 1)

    at S.T.P

  • Option 2)

    when V = 22.42 L

  • Option 3)

    when T = 12 K

  • Option 4)

    Impossible under any condition

 

Answers (1)

best_answer

PV= nRT

P= \frac{n}{V}RT;C=n/V

P= CRT\: \: \: \: \: ;\: \: \: \: T= \frac{P}{RC}= \frac{1\times 12}{1\times 1}= 12K

Ideal Gas Law -

PV=nRT

- wherein

P - Pressure

V - Volume

n - No. of Moles

R - Gas Constant

T - Temperature

 

 


Option 1)

at S.T.P

This is incorrect

Option 2)

when V = 22.42 L

This is incorrect

Option 3)

when T = 12 K

This is correct

Option 4)

Impossible under any condition

This is incorrect

Posted by

Aadil

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