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Focal length of the lens as shown in the figure is:

Option: 1

-5cm


Option: 2

-10cm


Option: 3

-15cm


Option: 4

-20cm


Answers (1)

best_answer

As we learn

Diverging lens -

If f is negative

- wherein

Happens when \left ( \mu -1 \right ) & \left ( \frac{1}{R_{1}}-\frac{1}{R_{2}} \right ) are of opposite sign.

 

 R1= -10cm        R2= 10cm

\mu=\frac{3}{2}

\frac{1}{f}=\left ( n_{rel-1} \right )\left ( \frac{1}{R_1}-\frac{1}{R_{2}} \right )=\left ( \frac{3}{2}-1 \right )\left ( \frac{1}{-10}-\frac{1}{10} \right )

f=-10cm

 

Posted by

Irshad Anwar

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