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A long narrow horizantal silt is placed 1mm above horizontal plane mirror the interference between the light coming directly from the silt and that after reflection is seen on a screen 1m away from the silt  if \lambda=700nm then fringe width is :

Option: 1

20mm


Option: 2

25mm


Option: 3

30mm


Option: 4

35mm


Answers (1)

best_answer

As we learn

Lloyd's mirror Experiment -

for minima-S_{2}P-S_{1}P= n\lambda

for maxima-S_{2}P-S_{1}P= \left ( n+1/2 \right )\lambda

 

 

 

\beta =\frac{\lambda D}{d}=\frac{700nm*1}{2mm}

          = 35mm      

 

Posted by

rishi.raj

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