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A certain mass of hydrogen is changed to He by the process of fusion. The mass defect in fusion reaction is 0.02866\mu. The energy liberated ( in MeV)  per \mu  is (1\mu=931MeV)

Option: 1

6.675


Option: 2

26.7


Option: 3

2.67


Option: 4

13.35


Answers (1)

best_answer

As we learn

Mass of electron,proton & neutron in terms of energy -

m_{e}=0.511\; Mev/c^{2}

m_{p}=938.27\; Mev/c^{2}

m_{n}=939.56\; Mev/c^{2}

1\, amu=931.5\; Mev/c^{2}

\begin{array}{l}{\text { As }^{2} \mathrm{H}+_{1}^{2} \mathrm{H} \rightarrow_{2}^{4} \mathrm{He}} \\ {\text { Here, } \Delta m=0.02866 \mathrm{u}}\end{array}

\begin{array}{l}{\therefore \text { The energy liberated per u is }} \\ \\{=\frac{\Delta M \times 931}{4} \mathrm{MeV}} \\ \\ {=\frac{0.02866 \times 931}{4} \mathrm{MeV}} \\ \\ {=\frac{26.7}{4} \mathrm{MeV}=6.675 \mathrm{MeV}}\end{array}

Posted by

jitender.kumar

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