Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

In x-ray diffraction first maxima occur at  \theta =300 then the wavelength of X-ray are

(d=1\AA):

Option: 1

1A^{\circ}


Option: 2

2A^{\circ}


Option: 3

3A^{\circ}


Option: 4

0.5A^{\circ}


Answers (1)

best_answer

 

 

 

 

Bragg's law -

2d\sin \Theta =n\lambda    

(condition of constructive maxima )

d=distance between parallel lines

\lambda = wavelength

\Theta = angle between light & plane

Here in X-ray diffraction n=1

2d\sin \theta =\lambda

\lambda =2*1A^{\circ} *\sin 30^{\circ}=1A^{\circ}

Posted by

Gautam harsolia

View full answer

Similar Questions

Latest Question