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Starting with the same initial conditions, an ideal gas expands from volume \mathrm{V_{1}} to \mathrm{V_{2}} in three different ways. The work done by the gas is \mathrm{W_{1}} if the process is purely isothermal, \mathrm{W_{2}}, if the process is purely adiabatic and \mathrm{W_{3}} if the process is purely isobaric. Then, choose the correct option

Option: 1

\mathrm{W_{1}<W_{2}<W_{3}}


Option: 2

\mathrm{W_{2}<W_{3}<W_{1}}


Option: 3

\mathrm{W_{3}<W_{1}<W_{2}}


Option: 4

\mathrm{W_{2}<W_{1}<W_{3}}


Answers (1)

best_answer

\text{area under P-V graph give work done.}

So \mathrm{W_{3}>W_{1}>W_{2}}

Hence the correct option is 4

Posted by

mansi

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