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  • Statement 1 : The line  meets the parabola, <img alt="y^{2}+2x=0" src="http://

Statement 1 : The line x-2y=2 meets the parabola, y^{2}+2x=0 only at the point  (-2, -2) :

Statement 2 : The line y=mx-\frac{1}{2m} (m\neq 0) is tangent to the parabola, y^{2}=-2x at the point \left ( -\frac{1}{2m^{2}},-\frac{1}{m} \right ).

Option: 1

Statement 1 is true ;Statement 2 is false 


Option: 2

Statement 1 is true ; Statement 2 is true ; Statement 2 is a correct explanation for Statement 1


Option: 3

Statement 1 is false  ; Statement 2 is true 


Option: 4

Statement 1 is true ; Statement 2 is true; Statement 2 is not a correct explanation of Statement 1


Answers (1)

best_answer

The straight line y=mx+\frac{a}{m} is always a tangent to the parabola y^{2}=4 a x for any value of m. The co-ordinates of point of contact \left(\frac{a}{m^{2}}, \frac{2 a}{m}\right).

Both statements are true and statement- 2 is the correct explanation of statement-1

Posted by

Sanket Gandhi

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