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  • Stationary waves of frequency are formed in a medium in which

Stationary waves of frequency \mathrm{300 \mathrm{~Hz}}are formed in a medium in which the velocity of sound is 200 \mathrm{~m} / \mathrm{s}. The distance between a node and the neighbouring antinode is-
 

Option: 1

1 \mathrm{~m}
 


Option: 2

2 \mathrm{~m}
 


Option: 3

3 \mathrm{~m}
 


Option: 4

4 \mathrm{~m}


Answers (1)

best_answer

Required distance \mathrm{=\frac{\lambda}{4}}

but \mathrm{\nu=n \lambda}

\mathrm{\lambda=\frac{\nu}{n} \quad} put in above equation.

Distance \mathrm{=\frac{v / n}{4}=\frac{1200}{4 \times 300}=1 \mathrm{~m}}

Hence option 1 is correct.

Posted by

Gautam harsolia

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