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  • Stuck here, help me understand: A particle is projected with a speed 4m/s along horizontal Direction from a height. The equation of its path is

A particle is projected with a speed 4m/s along horizontal Direction from a height. The equation of its path is 

  • Option 1) y=5x2/13

     

  • Option 2) y=13x2/16

     

  • Option 3) y=5x2/16

     

  • Option 4) y=3x2

     

 

Answers (1)

As we have learnt,

 

projectile motion when project of horizontally -

 

Equation of trajectory

y= \frac{g}{2u^{2}}.x^{2}

 

       

 

- wherein

u= horizontal velocity x and y are coordinates.

 

 x =4 t\;\;-(1)

y = \frac{1}{2}gt^2 = 5t^2 \;\; -(2)

From 1 and 2

y = \frac{5}{16}x^2


Option 1)

y = \frac{5}{13}x^2

Option 2)

y = \frac{13}{16}x^2

Option 3)

y = \frac{5}{16}x^2

Option 4)

y = 3x^2

Posted by

subam

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