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  • Stuck here, help me understand: - Atoms And Nuclei - JEE Main-6

A He^{+} ion is in its first excited state . Its ionization energy is :

  • Option 1)

    48.36\:\:eV

  • Option 2)

    54.40\:\:eV

  • Option 3)

    13.60\:\:eV

  • Option 4)

    6.04\:\:eV

 

Answers (1)

best_answer

we know that ,

E_{n}=-13.6 \left ( \frac{Z^{2}}{n^{2}} \right )

in first excited state for He^{+}

\Rightarrow n=2,Z=2

E=-13.6\times\left ( \frac{2^{2}}{2^{2}} \right )=-13.6\:eV

\Rightarrow Ionisation\:\:\:energy=+13.6\:eV

 


Option 1)

48.36\:\:eV

Option 2)

54.40\:\:eV

Option 3)

13.60\:\:eV

Option 4)

6.04\:\:eV

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