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  • Stuck here, help me understand: - In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength = 500n - Optics - JEE Main

In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength\lambda = 500nm is incident on the slits. The total number of bright fringes that are observed in the angular range -30^{\circ} \leq \theta \leq 30^{\circ} is:

 

  • Option 1)

    320

  • Option 2)

    321

  • Option 3)

    640

  • Option 4)

    641

Answers (1)

best_answer

 

Young Double Slit Experiment -

- wherein

y=\Delta x\cdot \left ( \frac{D}{d} \right )

y= Distance of a point on screen from central maxima

\Delta x= Path difference at that point

Path difference 

d\sin \theta =n\lambda

d\rightarrow separation of slits 

0.32\times 10^{-3}\sin 30^{\circ}=n\times 500\times 10^{-9}

n=320

number of maximas from -30\:\: to \: \: 30^{\circ}=2\times 320+1

                                                                  =641

 


Option 1)

320

Option 2)

321

Option 3)

640

Option 4)

641
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