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  • Stuck here, help me understand: - p- Block Elements - JEE Main

The states of hybridisation of boron and oxygen atoms in boric acid (H_{3}BO_{3}) are respectively

  • Option 1)

    sp^{2}\; \; and\; \; sp^{2}

  • Option 2)

    sp^{2}\; \; and\; \; sp^{3}

  • Option 3)

    sp^{3}\; \; and\; \; sp^{2}

  • Option 4)

    sp^{3}\; \; and\; \; sp^{3}

 

Answers (1)

As we learnt in 

Occurence of Boron -

Does not occur free in nature and its chief minerals are

Borax (or Tincal) - Na_{2}B_{4}O_{7}\cdot 10H_{2}O

Boric Acid  H_{3}BO_{3}

Kernite - Na_{2}B_{4}O_{7}\cdot 2H_{2}O

Colemanite - Ca_{2}B_{6}O_{11}\cdot 5H_{2}O

Boracite - 2Mg_{3}B_{8}O_{15}\cdot MgCl_{2}

-

 

 Each oxygen atom has 2 lone pairs and 2 bond pair making it sp3 hybridized.

B has 3 bond pairs making it sp2 hybridized.


Option 1)

sp^{2}\; \; and\; \; sp^{2}

This option is incorrect.

Option 2)

sp^{2}\; \; and\; \; sp^{3}

This option is correct.

Option 3)

sp^{3}\; \; and\; \; sp^{2}

This option is incorrect.

Option 4)

sp^{3}\; \; and\; \; sp^{3}

This option is incorrect.

Posted by

Sabhrant Ambastha

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