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Two liquids X and Y are perfectly immiscible. If X and Y have molecular masses in ratio 1 : 2, the total vapour pressure of a mixture of X and Y prepared in weight ratio 2 : 3 should be (P_{x}^{0} = 400\: torr, P_{y}^{0} = 200 \: torr)

  • Option 1)

    600\: torr

  • Option 2)

    400\: torr

  • Option 3)

    800 \: torr

  • Option 4)

    1000\: torr

 

Answers (1)

best_answer

As we learned 

 

Vapour Pressure of immiscible liquids -

P_{T}= P_{A}^{0}+P_{B}^{0}

(If stirred continuously )

P_{T}= P_{A}^{0}\or\ P_{B}^{0}

(Layer which is above )

 

-

 

 

Total vapour pressure of solution formed by immiscible liquid is sum of vapour pressures of pure liquid.

P_{total}=P_{X}^{0}+P_{Y}^{0}=400+200

=600torr

 


Option 1)

600\: torr

Option 2)

400\: torr

Option 3)

800 \: torr

Option 4)

1000\: torr

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Aadil

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