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Suppose metal react with the oxygen to form oxide, than aqueous solution of this oxide when added to a solution of HI, solution turn yellowish brown in colours. This compound is-
 

Option: 1

\mathrm{Na}_2 \mathrm{O}


Option: 2

\mathrm{Li}_2 \mathrm{O}


Option: 3

\mathrm{NaOH}


Option: 4

\mathrm{Na}_2 \mathrm{O}_2


Answers (1)

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\mathrm{Na}_2 \mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{Na}^{+}+2 \mathrm{OH}^{-}+\mathrm{H}_2 \mathrm{O}_2  aqueous solution of  \mathrm{Na}_2 \mathrm{O}_2  form \mathrm{H}_2 \mathrm{O}_2  which act as oxidizing agent hence, convert Iodide to Iodine \mathrm{\left(I_2\right).}
 

Posted by

Suraj Bhandari

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