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swimmer crosses the river along the line making an angle of 45º with the direction of flow. Velocity of the river is 5 m/s. Swimmer takes 6 seconds to cross the river of width 60 m. The velocity of the swimmer with respect to water will be:

Option: 1

10 m/s                                                                                 

 


Option: 2

12 m/s       


Option: 3

5\sqrt{5} m/s      


Option: 4

10m/s


Answers (1)

best_answer

River flow along y direction with a velocity of 5 j  m/s.
The swimmer crossover along the vector:  i + j  since angle is 45 degree
displacement of swimmer just after crossing = 60 i + 60 j  meters
speed of swimmer withrespect to to stationary observer
     = (60 i + 60 j) / 6  m/s = 10 i + 10 j   m/s
velocity of swimmer relative to the river = 10 i + 10 j - 5 j 
 magnitude of velocity relative to river = 5√5 m/s

 

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Pankaj

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