swimmer crosses the river along the line making an angle of 45º with the direction of flow. Velocity of the river is 5 m/s. Swimmer takes 6 seconds to cross the river of width 60 m. The velocity of the swimmer with respect to water will be:
10 m/s
12 m/s
m/s
10m/s
River flow along y direction with a velocity of 5 j m/s.
The swimmer crossover along the vector: i + j since angle is 45 degree
displacement of swimmer just after crossing = 60 i + 60 j meters
speed of swimmer withrespect to to stationary observer
= (60 i + 60 j) / 6 m/s = 10 i + 10 j m/s
velocity of swimmer relative to the river = 10 i + 10 j - 5 j
magnitude of velocity relative to river = 5√5 m/s
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